5. $\star$ Reduce the equation to one of the standard forms (a) $4 x^{2}+y^{2}+4 z^{2}-4 y-24 z+36=0$ (b) $x^{2}-y^{2}+z^{2}-2 x+2 y+4 z+2=0$

Step 1 ：Rewrite the given equations in their standard forms.

Step 2 ：Complete the square for the y and z terms in equation (a): $4x^2 + y^2 + 4z^2 - 4y - 24z + 36 = 0$

Step 3 ：Rewrite equation (a) in its standard form: \(\boxed{4x^2 + (y - 2)^2 + 4(z - 3)^2 = 4}\)

Step 4 ：Complete the square for the x, y, and z terms in equation (b): $x^2 - y^2 + z^2 - 2x + 2y + 4z + 2 = 0$

Step 5 ：Rewrite equation (b) in its standard form: \(\boxed{(x - 1)^2 - (y - 1)^2 + (z + 2)^2 = 1}\)