Using substitution, solve \[ \begin{aligned} 3 y-x & =-1 \\ x & =y+11 \end{aligned} \]

Step 1 ：Substitute the expression for x from the second equation into the first equation: \(3y - (y + 11) = -1\)

Step 2 ：Simplify the equation: \(2y - 11 = -1\)

Step 3 ：Add 11 to both sides: \(2y = 10\)

Step 4 ：Divide both sides by 2: \(y = 5\)

Step 5 ：Substitute the value of y back into the second equation: \(x = 5 + 11\)

Step 6 ：Solve for x: \(x = 16\)

Step 7 ：\(\boxed{x = 16, y = 5}\)