It is known that 100010539 is a prime number. What is the value of \[ 94^{100010538} \] in modulo $100010539 ?$ a. 0 b. 13 c. 15 d. 18 e. 17 f. 1 g. 5 h. 19

Step 1 ：Given that 100010539 is a prime number, we want to find the value of \(94^{100010538}\) in modulo 100010539.

Step 2 ：Using Fermat's Little Theorem, which states that if p is a prime number, then for any integer a, \(a^p \equiv a\) (mod p), we can rewrite the expression as \(94^{100010539-1} \pmod{100010539}\).

Step 3 ：According to Fermat's Little Theorem, this is equivalent to \(94^1 \pmod{100010539}\).

Step 4 ：Calculating the value of \(94^1 \pmod{100010539}\), we get \(\boxed{94}\) as the final answer.