Polynomial Description/Table to Standard May 26, 5:40:00 PM Watch help video The function $f(x)$ is a cubic function and the zeros of $f(x)$ are $-2,1$ and 2. The $y$ intercept of $f(x)$ is -8 . Write the equation of the cubic polynomial in standard form. Answel: $f(x)=$

Step 1 ：Given the zeros -2, 1, and 2, we can write the cubic function as: \(f(x) = a(x - (-2))(x - 1)(x - 2)\)

Step 2 ：Since the y-intercept is -8, we have \(f(0) = -8\). Plugging in x = 0, we get \(-8 = a(0 - (-2))(0 - 1)(0 - 2)\). Solving for a, we find that \(a = -2\)

Step 3 ：Substituting the value of a back into the equation, we get the final answer: \(\boxed{f(x) = -2(x - 2)(x - 1)(x + 2)}\)