Problem
The function \( f(x)=\frac{1}{1-2 \sin x} \) is discontinuous at \( f \) is continuous everywhere. \( x=0 \) \( x=\frac{\pi}{2} \) \( x=\frac{\pi}{6} \)
Solution
Step 1 ：\( 1-2 \sin x = 0 \)
Step 2 ：\( \sin x = \frac{1}{2} \)
Step 3 ：\( x = \frac{\pi}{6} \),\( \frac{5\pi}{6} \)
