What is the resultant magnitude of forces \( F 1+F 2 \), if \( F 1=40 \mathrm{kN}, \mathrm{F} 2=66 \mathrm{kN} \), angle "a" \( =220 \) degrees, and angle "b" \( =340 \) degrees? Use force units and two decimal points

Step 1 ：Calculate individual force components: \(F_{1x}=40\mathrm{kN}\cos{220}\degree\), \(F_{1y}=40\mathrm{kN}\sin{220}\degree\), \(F_{2x}=66\mathrm{kN}\cos{340}\degree\), \(F_{2y}=66\mathrm{kN}\sin{340}\degree\)

Step 2 ：Add force components: \(F_{x}=F_{1x}+F_{2x}\), \(F_{y}=F_{1y}+F_{2y}\)

Step 3 ：Calculate resultant magnitude: \(F=\sqrt{F_{x}^2+F_{y}^2}\)