Find the vertical asymptotes, if any, of the graph of the rational function. \[ h(x)=\frac{x+2}{x^{2}-4} \] (A) no vertical asymptote (B) $x=2, x=-2$ $x=2$ $x=-2$

Step 1 ：Find the values of x for which the denominator is equal to zero: \(x^2 - 4 = (x - 2)(x + 2)\)

Step 2 ：The denominator is zero when \(x = 2\) or \(x = -2\)

Step 3 ：Check if the numerator is also zero at these points: \(x + 2\)

Step 4 ：The numerator is zero when \(x = -2\)

Step 5 ：Since the numerator and denominator are both zero at \(x = -2\), it is not a vertical asymptote

Step 6 ：\(\boxed{x=2, x=-2}\) are the vertical asymptotes