Problem

The graph of $y=\sin x$ for $0^{\circ} \leq x \leq 360^{\circ}$ is shown below. Solve $\sin x=\sin 282^{\circ}$ for $0^{\circ} \leq x \leq 270^{\circ}$

Solution

Step 1 :\(\text{Solve } \sin x = \sin 282^\circ \text{ for } 0^\circ \leq x \leq 270^\circ\)

Step 2 :\(\text{Use the property of sine function: } \sin(x) = \sin(180 - x) \text{ and } \sin(x) = \sin(360 - x)\)

Step 3 :\(\sin 282^\circ = -0.9781476007338056\)

Step 4 :\(x_1 = 258.0^\circ\)

Step 5 :\(x_2 = 438.0^\circ\)

Step 6 :\(\text{Only } x_1 \text{ is within the given range}\)

Step 7 :\(\boxed{x = 258^\circ}\)

From Solvely APP
Source: https://solvelyapp.com/problems/16003/

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