Step 1 :First, let's find the value of \(\pi\). We know that \(2^\pi > 8102\).
Step 2 :\(\pi = 13\)
Step 3 :Now that we know the value of \(\pi\), we can calculate the sum of the first \(2^{(n-1)}\) natural numbers for each \(n\) in the range \([1, \pi]\). Then, we can find the sum of these values.
Step 4 :\(\pi = 13\)
Step 5 :\(\sum_{z=1}^{\pi} a_{z} = 11188906\)
Step 6 :\(\boxed{11188906}\)