Step 1 :The given function is \(\left(\frac{1}{2}\right)^{1-2 t}\).
Step 2 :We can rewrite it in the form \(f(t)=k a^{t}\) by using the properties of exponents.
Step 3 :The properties of exponents state that \(a^{m-n} = \frac{a^m}{a^n}\).
Step 4 :So, we can rewrite the given function as \(\frac{1}{2}^{1} \cdot \frac{1}{2}^{-2t}\).
Step 5 :Then, we can simplify this to \(\frac{1}{2} \cdot 2^{2t}\).
Step 6 :Finally, we can rewrite this as \(2^{2t-1}\).
Step 7 :The function in the form \(f(t)=k a^{t}\) is \(f(t)=1 \cdot 2^{2t-1}\).
Step 8 :\(\boxed{f(t)=2^{2t-1}}\) is the final answer.