Step 1 :Given the function \(f(x) = x^2 + 4\) and the point \(P(5,29)\).
Step 2 :The slope of the tangent line to the graph of the function at a point is given by the derivative of the function at that point.
Step 3 :Find the derivative of the function \(f(x) = x^2 + 4\), which is \(f'(x) = 2x\).
Step 4 :Evaluate the derivative at \(x = 5\) to find the slope of the tangent line, which is \(f'(5) = 2*5 = 10\).
Step 5 :Use the point-slope form of the equation of a line, \(y - y_1 = m(x - x_1)\), to find the equation of the tangent line. Here, \(m = 10\) and \((x_1, y_1) = (5, 29)\).
Step 6 :Substitute the values into the equation to get \(y - 29 = 10(x - 5)\).
Step 7 :Simplify the equation to get \(y = 10x - 21\).
Step 8 :Final Answer: The equation of the tangent line to the graph of the function \(f(x) = x^2 + 4\) at the point \(P(5,29)\) is \(\boxed{y = 10x - 21}\).