$4.3 \mathrm{ft}$ 46. Max's dog is lying on the ground $1.2 \mathrm{~m}$ away from him. The angle of elevation from the dog to the top of Max's head is $48^{\circ}$. How tall is Max, to the nearest tenth of a metre?

Step 1 ：Let the height of Max be denoted as h. We have a right triangle with angle 48 degrees, opposite side h, and adjacent side 1.2 meters.

Step 2 ：Using the tangent function, we can write the equation: \(\tan(48) = \frac{h}{1.2}\)

Step 3 ：Multiplying both sides by 1.2, we get: \(h = \tan(48) \times 1.2\)

Step 4 ：Calculating the height, we find: \(h \approx 1.3327350177950315\)

Step 5 ：Rounding to the nearest tenth, we get the final answer: \(\boxed{1.3}\) meters