Problem

\[ f(x)=\sqrt[3]{x}+5 \] Plot five points on the graph of the function, as follows. - Plot the first point using the $x$-value that satisfies $\sqrt[3]{x}=0$. - Plot two points to the left and two points to the right of the first point. Then click on the graph-a-function button.

Solution

Step 1 :First, find the x-value that satisfies \(\sqrt[3]{x}=0\). The cube root of 0 is 0, so the first point is (0,5), because when we substitute x=0 into the function, we get f(0)=5.

Step 2 :Next, find two points to the left and two points to the right of the first point. Choose x-values that are less than 0 and greater than 0, respectively. For simplicity, choose x=-1 and x=-2 for the points to the left, and x=1 and x=2 for the points to the right.

Step 3 :Substitute these x-values into the function to find the corresponding y-values. This will give the coordinates of the points to plot on the graph.

Step 4 :The five points to plot on the graph of the function are \((-2, 3.74), (-1, 4.0), (0, 5.0), (1, 6.0), (2, 6.26)\)

Step 5 :\(\boxed{\text{Final Answer: The five points to plot on the graph of the function are } (-2, 3.74), (-1, 4.0), (0, 5.0), (1, 6.0), (2, 6.26)}\)

From Solvely APP
Source: https://solvelyapp.com/problems/15877/

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