Solve $2 x(6-5 x)=-7$ Give your answers to 2 d.p.

Step 1 ：Expand the equation: \(2x(6-5x) = 2x(6) - 2x(5x) = 12x - 10x^2\)

Step 2 ：Set the equation equal to -7: \(12x - 10x^2 = -7\)

Step 3 ：Rearrange the equation: \(10x^2 - 12x + 7 = 0\)

Step 4 ：Use the quadratic formula to solve for x: \(x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)

Step 5 ：Plug in the values: \(x = \frac{12 \pm \sqrt{(-12)^2 - 4(10)(7)}}{2(10)}\)

Step 6 ：Simplify the expression: \(x = \frac{12 \pm \sqrt{144 - 280}}{20}\)

Step 7 ：Further simplify: \(x = \frac{12 \pm \sqrt{-136}}{20}\)

Step 8 ：Calculate the two solutions: \(x = \frac{3}{5} - \frac{\sqrt{106}}{10}, x = \frac{3}{5} + \frac{\sqrt{106}}{10}\)

Step 9 ：Round the solutions to 2 decimal places: \(x = -0.43, x = 1.63\)

Step 10 ：\(\boxed{x = -0.43, x = 1.63}\)