Problem

Find the derivative of the following function. \[ y=e^{-x} \sin x \]

Solution

Step 1 :We are given the function \(y=e^{-x} \sin x\).

Step 2 :We need to find the derivative of this function.

Step 3 :To do this, we will use the product rule and the chain rule.

Step 4 :The product rule is used when differentiating the product of two functions, and the chain rule is used when differentiating the composition of two functions.

Step 5 :In this case, the function is the product of \(e^{-x}\) and \(\sin x\), so we will need to use the product rule.

Step 6 :The function \(e^{-x}\) is also the composition of \(e^x\) and \(-x\), so we will need to use the chain rule to differentiate it.

Step 7 :Applying the product rule, we get \(dy/dx = -e^{-x}\sin x + e^{-x}\cos x\).

Step 8 :\(\boxed{-e^{-x}\sin x + e^{-x}\cos x}\) is the final answer.

From Solvely APP
Source: https://solvelyapp.com/problems/15774/

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