In a class of 18 sstudent there are 10 men and 8 women. Four students are selected to present a demonstration on the use of graphing calculators. Find the probability that the group consists of (d)One man and three women. Round your answer to five decimal places. The probability that the group consists of one man and three women is

Step 1 ：The problem is asking for the probability of selecting one man and three women from a group of 18 students, where there are 10 men and 8 women. This is a combination problem, because the order of selection does not matter.

Step 2 ：The total number of ways to select 4 students out of 18 is given by the combination formula \(C(n, k) = \frac{n!}{k!(n-k)!}\), where n is the total number of students (18), k is the number of students to select (4), and '!' denotes factorial.

Step 3 ：The number of ways to select one man out of 10 is \(C(10, 1)\), and the number of ways to select three women out of 8 is \(C(8, 3)\).

Step 4 ：The probability of selecting one man and three women is then given by the ratio of the number of favorable outcomes (one man and three women) to the total number of outcomes (any four students).

Step 5 ：Calculating the total number of ways to select 4 students out of 18, we get 3060.

Step 6 ：Calculating the number of ways to select one man out of 10 and three women out of 8, we get 560.

Step 7 ：Dividing the number of favorable outcomes by the total number of outcomes, we get a probability of approximately 0.1830065359477124.

Step 8 ：Final Answer: The probability that the group consists of one man and three women is approximately \(\boxed{0.18301}\).