3. Which ratio gives the value of $\sin C$ for $\triangle A B C$ ? a) $\sin C=\frac{a}{b}$ b) $\sin C=\frac{b}{c}$ c) $\sin C=\frac{c}{b}$ d) $\sin C=\frac{a}{c}$

Step 1 ：Which ratio gives the value of \(\sin C\) for \(\triangle A B C\) ?

Step 2 ：Using the sine rule, we have \(\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C}\)

Step 3 ：Solving for \(\sin C\), we get \(\sin C = \frac{c \sin A}{a}\)

Step 4 ：None of the given options match the expression we derived for \(\sin C\)

Step 5 ：\(\boxed{\text{None of the given options}}\)