The solution set of The equation \( X^{2}+4=0 \) in \( \mathrm{R} \) is.......

Step 1 ：Rewrite as \(X^{2}=-4\)

Step 2 ：Since no real number squared equals a negative number, there are no solutions in \( \mathrm{R} \)

Step 3 ：Therefore, the solution set is \( \emptyset \)