Question 1 (1 point) In $\triangle A B C, \angle B=90^{\circ}, b=12 \mathrm{~cm}$, and $c=8 \mathrm{~cm}$. Determine the measure of $\angle A$. $34^{\circ}$ $48^{\circ}$ $0.99^{\circ}$ $42^{\circ}$

Step 1 ：Given a right triangle $\triangle ABC$ with $\angle B = 90^\circ$, side $b = 12 \text{ cm}$, and side $c = 8 \text{ cm}$. We need to find the measure of $\angle A$. We can use the tangent function since we have the opposite (b) and adjacent (c) sides.

Step 2 ：The tangent function is defined as: $\tan(A) = \frac{\text{opposite}}{\text{adjacent}} = \frac{b}{c}$

Step 3 ：We can find the angle A by taking the inverse tangent ($\arctan$) of the ratio $\frac{b}{c}$: $A = \arctan(\frac{12}{8})$

Step 4 ：Calculating the inverse tangent, we get $A \approx 56.31^\circ$

Step 5 ：\(\boxed{\text{The measure of } \angle A \text{ is approximately } 56.31^\circ}\)