Given the function $f(x)=x^{3}+9 x^{2}+14 x-14$, determine all coordinate points $(x, y)$ on the graph of $f$ such that the line tangent to $f$ at $(x, y)$ has a slope of -1 .

Step 1 ：Given the function \(f(x)=x^{3}+9 x^{2}+14 x-14\), determine all coordinate points \((x, y)\) on the graph of \(f\) such that the line tangent to \(f\) at \((x, y)\) has a slope of -1.

Step 2 ：Find the derivative of \(f(x)\): \(f'(x) = 3x^2 + 18x + 14\)

Step 3 ：Set the derivative equal to -1: \(3x^2 + 18x + 14 = -1\)

Step 4 ：Solve for x: \(x = -5, -1\)

Step 5 ：Find the corresponding y values: \(y = f(-5) = 16, f(-1) = -20\)

Step 6 ：\(\boxed{(-5, 16), (-1, -20)}\)