Greg and Martin each have a different sized mug. Greg fills his mug with water 3 times, each time pouring the water into measuring jug A. Martin fills his mug with water 6 times, each time pouring the water into measuring jug $B$. Calculate how many more millilitres of water Martin's mug holds than Greg's. Measuring jug B < Back to task Watch video

Step 1 ：Let the volume of Greg's mug be \(G\) millilitres and the volume of Martin's mug be \(M\) millilitres.

Step 2 ：Greg fills his mug 3 times, so the total volume of water in jug A is \(3G\) millilitres.

Step 3 ：Martin fills his mug 6 times, so the total volume of water in jug B is \(6M\) millilitres.

Step 4 ：We are asked to find the difference in volume between Martin's mug and Greg's mug, which is \(M - G\) millilitres.

Step 5 ：Since the total volume of water in jug A is equal to the total volume of water in jug B, we have \(3G = 6M\).

Step 6 ：Divide both sides of the equation by 3 to get \(G = 2M\).

Step 7 ：Substitute this expression for \(G\) into the difference \(M - G\) to get \(M - 2M = -M\).

Step 8 ：The difference in volume between Martin's mug and Greg's mug is \(\boxed{-M}\) millilitres.