Problem
Each side length of Cube $A$ is $4 \mathrm{~cm}$ long. Each side length of Cube $B$ is triple the side length of Cube $A$. How many times greater is the volume of Cube $B$ than that of Cube A? 1664 times 192 times 27 times 9 times
Solution
Step 1 ：Let the side length of Cube A be \(a\) and the side length of Cube B be \(b\). Given that \(b = 3a\), and \(a = 4\) cm.
Step 2 ：Calculate the volume of Cube A: \(V_A = a^3 = 4^3 = 64\) cubic cm.
Step 3 ：Calculate the side length of Cube B: \(b = 3a = 3(4) = 12\) cm.
Step 4 ：Calculate the volume of Cube B: \(V_B = b^3 = 12^3 = 1728\) cubic cm.
Step 5 ：Find how many times greater the volume of Cube B is than that of Cube A: \(\frac{V_B}{V_A} = \frac{1728}{64} = 27\).
Step 6 ：\(\boxed{27}\) times greater.
