Question 3 Flag this question. Each side length of Cube $A$ is $4 \mathrm{~cm}$ long. Each side length of Cube $B$ is triple the side length of Cube $A$. How many times greater is the volume of Cube $B$ than that of Cube $A$ ? \[ 1664 \text { times } \quad 192 \text { times } \] 27 times 9 times

Step 1 ：Let the side length of Cube A be \(a\) and the side length of Cube B be \(b\). Given that each side length of Cube A is \(4\mathrm{~cm}\) long, we have \(a = 4\).

Step 2 ：Since each side length of Cube B is triple the side length of Cube A, we have \(b = 3a = 3(4) = 12\).

Step 3 ：To find the volume of Cube A, we use the formula \(V_A = a^3 = 4^3 = 64\mathrm{~cm^3}\).

Step 4 ：To find the volume of Cube B, we use the formula \(V_B = b^3 = 12^3 = 1728\mathrm{~cm^3}\).

Step 5 ：Finally, we find the ratio of the volume of Cube B to the volume of Cube A: \(\frac{V_B}{V_A} = \frac{1728}{64} = 27\).

Step 6 ：\(\boxed{27}\) times greater is the volume of Cube B than that of Cube A.