d) $\sqrt{100}-\sqrt[3]{64}$ e) $-\sqrt{121}+\sqrt{196}$ Calcule as adiçőes algébricas. a) $\sqrt{10}+2 \sqrt{10}-5 \sqrt{10}$ b) $3 \sqrt{8}-\sqrt{18}+2 \sqrt{32}$ c) $\sqrt[3]{81}+2 \sqrt[3]{24}-3 \sqrt[3]{375}$ d) $\sqrt{50}-\sqrt{300}-\sqrt{98}+\sqrt{363}$ e) $5 \sqrt{8}-2 \sqrt{18}+\frac{1}{2} \sqrt{200}$ ) $\sqrt[3]{128}-\sqrt[3]{250}+\sqrt[3]{54}-\sqrt[3]{16}$ g) $\sqrt[3]{375}-\sqrt[3]{24}+\sqrt[3]{81}-\sqrt[3]{19}$ h) $3 x \sqrt{x y^{3}}-x y \sqrt{4 x y}-2 \sqrt{x^{3} y^{3}}$

Step 1 ：\(a) \sqrt{10}+2 \sqrt{10}-5 \sqrt{10} = (1+2-5)\sqrt{10} = \boxed{-2\sqrt{10}}\)

Step 2 ：\(b) 3 \sqrt{8}-\sqrt{18}+2 \sqrt{32} = 3(2\sqrt{2}) - 3\sqrt{2} + 2(4\sqrt{2}) = (6-3+8)\sqrt{2} = \boxed{11\sqrt{2}}\)

Step 3 ：\(c) \sqrt[3]{81}+2 \sqrt[3]{24}-3 \sqrt[3]{375} = 3\sqrt[3]{3} + 2\sqrt[3]{8} - 3\sqrt[3]{125} = 3\sqrt[3]{3} + 2(2) - 3(5) = \boxed{3\sqrt[3]{3} - 1}\)

Step 4 ：\(d) \sqrt{50}-\sqrt{300}-\sqrt{98}+\sqrt{363} = 5\sqrt{2} - 10\sqrt{3} - 7\sqrt{2} + 11\sqrt{3} = (5-7)\sqrt{2} + (-10+11)\sqrt{3} = \boxed{-2\sqrt{2} + \sqrt{3}}\)

Step 5 ：\(e) 5 \sqrt{8}-2 \sqrt{18}+\frac{1}{2} \sqrt{200} = 5(2\sqrt{2}) - 2(3\sqrt{2}) + \frac{1}{2}(10\sqrt{2}) = (10-6+5)\sqrt{2} = \boxed{9\sqrt{2}}\)

Step 6 ：\(f) \sqrt[3]{128}-\sqrt[3]{250}+\sqrt[3]{54}-\sqrt[3]{16} = 4\sqrt[3]{2} - 5\sqrt[3]{2} + 3\sqrt[3]{2} - 2 = (4-5+3)\sqrt[3]{2} - 2 = \boxed{2\sqrt[3]{2} - 2}\)

Step 7 ：\(g) \sqrt[3]{375}-\sqrt[3]{24}+\sqrt[3]{81}-\sqrt[3]{19} = 5\sqrt[3]{3} - 2\sqrt[3]{3} + 3\sqrt[3]{3} - \sqrt[3]{19} = (5-2+3)\sqrt[3]{3} - \sqrt[3]{19} = \boxed{6\sqrt[3]{3} - \sqrt[3]{19}}\)

Step 8 ：\(h) 3 x \sqrt{x y^{3}}-x y \sqrt{4 x y}-2 \sqrt{x^{3} y^{3}} = 3xy\sqrt{y} - 2xy\sqrt{2xy} - 2xy\sqrt{xy} = (3xy\sqrt{y} - 2xy\sqrt{2xy} - 2xy\sqrt{xy}) = \boxed{3xy\sqrt{y} - 2xy\sqrt{2xy} - 2xy\sqrt{xy}}\)