Of 1,000 students surveyed, 530 were boys and 180 had bicycles. Of those who had bicycles, 30 were girls. What is the probability that a student surveyed was either a boy or had a bicycle?

Step 1 ：Find the probabilities of each event and their intersection: \(P(A) = \frac{530}{1000} = 0.53\), \(P(B) = \frac{180}{1000} = 0.18\), \(P(A \cap B) = \frac{150}{1000} = 0.15\)

Step 2 ：Use the formula for the probability of the union of two events: \(P(A \cup B) = P(A) + P(B) - P(A \cap B) = 0.53 + 0.18 - 0.15 = 0.56\)

Step 3 ：\boxed{0.56}