Problem

Note: Figures not drawn to scale. The angles shown above are acute and $\sin \left(a^{\circ}\right)=\cos \left(b^{\circ}\right)$. If $a=4 k-22$ and $b=6 k-13$, what is the value of $k$ ? A) 4.5 B) 5.5 C) 12.5 D) 21.5

Solution

Step 1 :Given that $a=4k-22$ and $b=6k-13$, and $a+b=90$

Step 2 :Substitute the values of $a$ and $b$ into the equation: $(4k-22) + (6k-13) = 90$

Step 3 :Simplify the equation: $10k - 35 = 90$

Step 4 :Add 35 to both sides: $10k = 125$

Step 5 :Divide both sides by 10: $k = \frac{25}{2}$

Step 6 :\(\boxed{k = 12.5}\)

From Solvely APP
Source: https://solvelyapp.com/problems/15402/

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