Step 1 :\(A\) is the intersection of \(y = 3x + 1\) and \(y = -5x + 15\). We solve the system of equations:
Step 2 :\(3x + 1 = -5x + 15\)
Step 3 :\(8x = 14\)
Step 4 :\(x = \frac{7}{4}\)
Step 5 :Substitute \(x\) back into either equation to find \(y\):
Step 6 :\(y = 3\left(\frac{7}{4}\right) + 1\)
Step 7 :\(y = \frac{15}{4}\)
Step 8 :So, \(A\) has coordinates \(\boxed{\left(\frac{7}{4}, \frac{15}{4}\right)}\)
Step 9 :\(C\) is the intersection of \(y = -5x + 15\) and the \(x\)-axis. When a point is on the \(x\)-axis, its \(y\)-coordinate is 0:
Step 10 :\(0 = -5x + 15\)
Step 11 :\(5x = 15\)
Step 12 :\(x = 3\)
Step 13 :So, \(C\) has coordinates \(\boxed{(3, 0)}\)