Investments increase exponentially by about $26 \%$ every 3 years. If you made a $\$ 2000$ investment, how much money would you have after 45 years? Future Amount $=[?](1+[])$ Future Amount $=\mathrm{I}(1+r)^{\mathrm{t}}$

Step 1 ：Calculate the number of time periods (3-year intervals) in 45 years: \(\frac{45}{3} = 15\) time periods

Step 2 ：Use the compound interest formula: Future Amount = Initial Investment * \((1 + Interest Rate)^{Time Periods}\)

Step 3 ：Plug in the values: Future Amount = \(2000 * (1 + 0.26)^{15}\)

Step 4 ：Calculate the future amount: Future Amount = \(2000 * (1.26)^{15}\) = 64060.182624413

Step 5 ：\(\boxed{After 45 years, the investment would be worth approximately $64,060.18}\)