Problem

Given $P(A)=0.51, P(B)=0.7$ and $P(A \cap B)=0.477$, find the value of $P(A \cup B)$, rounding to the nearest thousandth, if necessary.

Solution

Step 1 :Given \(P(A)=0.51\), \(P(B)=0.7\) and \(P(A \cap B)=0.477\), find the value of \(P(A \cup B)\), rounding to the nearest thousandth, if necessary.

Step 2 :We need to find the probability of \(P(A \cup B)\). We can use the formula for the probability of the union of two events: \(P(A \cup B) = P(A) + P(B) - P(A \cap B)\).

Step 3 :\(P(A \cup B) = 0.51 + 0.7 - 0.477\)

Step 4 :\(P(A \cup B) = 0.733\)

Step 5 :\(\boxed{0.733}\)

From Solvely APP
Source: https://solvelyapp.com/problems/14760/

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