Problem

Simplify the given expression: $\frac{x^{2}+3 x-4}{x^{2}-x-20}=$

Solution

Step 1 :Given the expression \(\frac{x^{2}+3 x-4}{x^{2}-x-20}\)

Step 2 :To simplify it, we can factorize the numerator and the denominator.

Step 3 :The factorized form of the numerator \(x^{2}+3 x-4\) is \((x - 1)(x + 4)\)

Step 4 :The factorized form of the denominator \(x^{2}-x-20\) is \((x - 5)(x + 4)\)

Step 5 :After factorizing, we can cancel out the common factors from the numerator and the denominator, which is \((x + 4)\)

Step 6 :So, the simplified expression is \(\frac{x - 1}{x - 5}\)

Step 7 :Final Answer: The simplified form of the given expression is \(\boxed{\frac{x-1}{x-5}}\)

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Source: https://solvelyapp.com/problems/13ybp4IHJW/

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