Step 1 :We are given the following values: the number of students who sit in the front of the class (\(n1\)) is 35, their mean study hours per week (\(\bar{x1}\)) is 17.26, and their standard deviation (\(s1\)) is 9.34. The number of students who sit in the back of the class (\(n2\)) is 36, their mean study hours per week (\(\bar{x2}\)) is 11.08, and their standard deviation (\(s2\)) is 8.64.
Step 2 :We are testing the claim that the average weekly number of hours spent studying by students who sit in the front of the classroom is greater than that of students who sit in the back of the classroom. This is a two-sample t-test.
Step 3 :The test statistic for a two-sample t-test is calculated using the formula: \(t = \frac{(\bar{x1} - \bar{x2}) - 0}{\sqrt{(s1^2/n1) + (s2^2/n2)}}\)
Step 4 :Substituting the given values into the formula, we get: \(t = \frac{(17.26 - 11.08) - 0}{\sqrt{(9.34^2/35) + (8.64^2/36)}}\)
Step 5 :Solving the above expression, we find that the test statistic \(t\) is approximately 2.892
Step 6 :Final Answer: The value of the test statistic used in the hypothesis test is \(\boxed{2.892}\)