The $n$th term of an arithmetic sequence is given. \[ a_{n}=3+2(n-1) \] (a) Find the first five terms of the sequence. \[ \begin{array}{l} a_{1}= \\ a_{2}= \\ a_{3}= \\ a_{4}= \\ a_{5}= \end{array} \] (b) What is the common difference $d$ ? \[ d= \]

Step 1 ：Substitute the values 1, 2, 3, 4, and 5 into the formula for \(a_n\) to find the first five terms of the sequence.

Step 2 ：\(a_1 = 3 + 2(1 - 1) = 3\)

Step 3 ：\(a_2 = 3 + 2(2 - 1) = 5\)

Step 4 ：\(a_3 = 3 + 2(3 - 1) = 7\)

Step 5 ：\(a_4 = 3 + 2(4 - 1) = 9\)

Step 6 ：\(a_5 = 3 + 2(5 - 1) = 11\)

Step 7 ：Subtract \(a_{n-1}\) from \(a_n\) to find the common difference \(d\).

Step 8 ：\(d = a_2 - a_1 = 5 - 3 = 2\)

Step 9 ：The first five terms of the sequence are \(\boxed{3, 5, 7, 9, 11}\) and the common difference \(d\) is \(\boxed{2}\)