If $A=\left\{x ; x^{3}-3 x^{2}+2 x=0\right\}, B=\left\{x ; x^{2}-2 x=0\right\}$ then $A \cup B$ is

Step 1 ：Solve the equations: \(x^3 - 3x^2 + 2x = 0\) and \(x^2 - 2x = 0\) to find the elements of sets A and B

Step 2 ：A = \{0, 1, 2\}, B = \{0, 2\}

Step 3 ：\boxed{A \cup B = \{0, 1, 2\}}