Problem

Negative Marks : -1 If wrong option is selected. Given $n(U)=20, n(A)=12, n(B)=9, n(A \cap B)=4$, where $U$ is universal set, $A \& B$ are subsets of $U$, then $\left(n(A \cup B)^{\prime}\right)$ equals :-

Solution

Step 1 :Find the union of sets A and B using the formula: \(n(A \cup B) = n(A) + n(B) - n(A \cap B)\)

Step 2 :Calculate the complement of the union by subtracting the result from the total number of elements in the universal set: \(n((A \cup B)') = n(U) - n(A \cup B)\)

Step 3 :Plug in the given values: \(n(U) = 20, n(A) = 12, n(B) = 9, n(A \cap B) = 4\)

Step 4 :Calculate the union: \(n(A \cup B) = 12 + 9 - 4 = 17\)

Step 5 :Calculate the complement: \(n((A \cup B)') = 20 - 17 = 3\)

Step 6 :\(\boxed{n((A \cup B)') = 3}\)

From Solvely APP
Source: https://solvelyapp.com/problems/13273/

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