A bag contains 7 red marbles, 2 blue marbles and 5 green marbles. If two marbles are drawn out of the bag, what is the probability, to the nearest $10 t h$ of a percent, that both marbles drawn will be blue?

Step 1 ：Calculate the total number of marbles: 7 red + 2 blue + 5 green = 14 marbles

Step 2 ：Find the total number of possible outcomes when drawing two marbles: \(\binom{14}{2} = 91\)

Step 3 ：Find the number of successful outcomes (drawing 2 blue marbles): \(\binom{2}{2} = 1\)

Step 4 ：Calculate the probability: \(\frac{1}{91} \approx 0.011\)

Step 5 ：Convert the probability to a percentage: \(0.011 \times 100 = 1.1\%\)

Step 6 ：\(\boxed{1.1\%}\)