Suppose that the confidence interval $(0.56,0.76)$ is given for a population proportion, $p$. Use these confidence interval limits to find the point estimate, $\widehat{p}$, and the margin of error, $E$.

Step 1 ：Given the confidence interval for a population proportion, \(p\), is \((0.56,0.76)\).

Step 2 ：The point estimate, \(\widehat{p}\), is the midpoint of the confidence interval. It can be calculated as the average of the lower and upper limits of the confidence interval.

Step 3 ：Calculate the point estimate, \(\widehat{p}\), as \((0.56 + 0.76) / 2 = 0.66\).

Step 4 ：The margin of error, \(E\), is the difference between the point estimate and either the lower or upper limit of the confidence interval.

Step 5 ：Calculate the margin of error, \(E\), as \(0.66 - 0.56 = 0.10\).

Step 6 ：Final Answer: The point estimate, \(\widehat{p}\), is \(\boxed{0.66}\) and the margin of error, \(E\), is approximately \(\boxed{0.10}\).