Find $\frac{d^{2} y}{d x^{2}}$ \[ y=\sqrt[3]{x} \] \[ \frac{d^{2} y}{d x^{2}}= \]

Step 1 ：Find the first derivative of the function \(y=\sqrt[3]{x}\). The derivative is \(y'=\frac{1}{3}x^{-\frac{2}{3}}\).

Step 2 ：Find the second derivative by taking the derivative of the first derivative. The second derivative of the function \(y=\sqrt[3]{x}\) is \(y''=-\frac{2}{9}x^{-\frac{5}{3}}\).

Step 3 ：Final Answer: The second derivative of the function \(y=\sqrt[3]{x}\) is \(\boxed{-\frac{2}{9}x^{-\frac{5}{3}}}\).