Step 1 :Given the volume formula for a right triangular pyramid: V = (1/3) * (1/2) * leg1 * leg2 * h
Step 2 :Plug in the known values: 40.15 = (1/3) * (1/2) * 13.2 * leg2 * 5
Step 3 :Solve for leg2: leg2 = \(\frac{40.15 * 3 * 2}{13.2 * 5}\)
Step 4 :Calculate leg2: leg2 ≈ 3.65
Step 5 :\(\boxed{\text{Final Answer: The leg 2 of the base of the right triangular pyramid is approximately 3.65 ft.}}\)