Which point satisfies the inequality $3 x-2 y \leq 10$ ? $(7,1) \quad(5,-3)$ $(3,5) \quad(-1,-7)$

Step 1 ：Check which of the given points satisfy the inequality \(3x - 2y \leq 10\):

Step 2 ：For point (7, 1): \(3(7) - 2(1) = 21 - 2 = 19 \), 19 is not less than or equal to 10.

Step 3 ：For point (5, -3): \(3(5) - 2(-3) = 15 + 6 = 21 \), 21 is not less than or equal to 10.

Step 4 ：For point (3, 5): \(3(3) - 2(5) = 9 - 10 = -1 \), -1 is less than or equal to 10.

Step 5 ：For point (-1, -7): \(3(-1) - 2(-7) = -3 + 14 = 11 \), 11 is not less than or equal to 10.

Step 6 ：\boxed{(3, 5)} is the point that satisfies the inequality \(3x - 2y \leq 10\)