Problem
(2) Ruselana inginder ear plo ataina: $\sqrt{4.25}=\sqrt{4} \cdot \sqrt{25}=2.5=10$ a) $\sqrt{57}$ f) $\sqrt[4]{9 \cdot x^{3} \cdot y^{5}}$ f) $\sqrt[3]{28}$ c) $\sqrt[3]{5 x}$ a) $\sqrt{10 x y}$ e) $\sqrt{5 x^{2} m}$ (3.) Aplicande as dua (1) e(2), resolva: a) $\sqrt[3]{2^{3} \cdot f^{3}}$ b) $\sqrt[5]{9 \cdot x^{3} \cdot y^{5}}$
Solution
Step 1 ：\(\sqrt{57} \approx 7.55\)
Step 2 ：\(\sqrt[3]{28} \approx 3.04\)
