A. $y=\frac{2}{3} x-4$ B. $y=\frac{2}{3} x+6$ C. $y=\frac{3}{2} x-4$ D. $y=-4 x+\frac{2}{3}$

Step 1 ：Find the slope of the given line: \(m = \frac{2}{3}\)

Step 2 ：Since parallel lines have the same slope, use the slope and the point (0, 6) to find the equation of the new line: \(y = \frac{2}{3}x + b\)

Step 3 ：Plug in the point (0, 6) to find the y-intercept: \(6 = \frac{2}{3}(0) + b\)

Step 4 ：Solve for b: \(b = 6\)

Step 5 ：Write the equation of the line: \(y = \frac{2}{3}x + 6\)

Step 6 ：\(\boxed{y = \frac{2}{3}x + 6}\)