Problem

A bank teller cashed a check for \( \$ 1190 \) using \( \$ 50 \) bills and \( \$ 10 \) bills. The teller handed 13 more \( \$ 50 \) bills than \( \$ 10 \) bills to the customer customer. How many \( \$ 50 \) dollar bills were handed to the customer?

Solution

Step 1 :Let x be the number of \(\$ 50\) bills and y be the number of \(\$ 10\) bills.

Step 2 :Set up equations: 50x + 10y = 1190 and x = y + 13.

Step 3 :Substitute the second equation into the first equation: 50(y + 13) + 10y = 1190.

Step 4 :Simplify and solve for y: 60y + 650 = 1190 \Rightarrow y = 9.

Step 5 :Substitute the value of y into the x = y + 13 equation: x = 9 + 13.

Step 6 :Calculate x: x = 22

From Solvely APP
Source: https://solvelyapp.com/problems/10636/

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