Find the surface area of a square pyramid with side length \( 5 \mathrm{~m} \) and slant height \( 6 \mathrm{~m} \).

Step 1 ：\(A_{base} = 5^2 = 25 \mathrm{m}^2 \)

Step 2 ：\(A_{lateral} = 4 \times \frac{1}{2} (5)(6) = 4(15) = 60 \mathrm{m}^2 \)

Step 3 ：\(A_{total} = A_{base} + A_{lateral} = 25 + 60 = 85 \mathrm{m}^2 \)