Problem
You have found the following ages (in years) of all 4 bears at your local zoo: \( 5,4,6,39 \) What is the average age of the bears at your zoo? What is the standard deviation? Round your answers to the nearest tenth.
Solution
Step 1 ：\( \text{Average} = \frac{5+4+6+39}{4} = \frac{54}{4} \)
Step 2 ：\( \text{Deviation} : (5-13.5)^2,(4-13.5)^2,(6-13.5)^2,(39-13.5)^2 \)
Step 3 ：\( \text{Standard Deviation} = \sqrt{ \frac{(5-13.5)^2+(4-13.5)^2+(6-13.5)^2+(39-13.5)^2}{4} } \approx 14.6 \)
