An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such that it would produce a mean pressure of 6.8 pounds/square inch it is believed that the valve performs above the specifications. The valve was tested on 24 engines and the mean pressure was 7.1 pounds/square inch with a standard deviation of 0.7 . A level of significance of 0,1 will be used. Assume the population distribution is approximately normal Determine the dedsion rule for rejecting the nuil hypothesis. Round your answer to three decimal places

Step 1 ：Define the null hypothesis as the mean pressure being 6.8 pounds/square inch and the alternative hypothesis as the mean pressure being greater than 6.8 pounds/square inch.

Step 2 ：Calculate the z-score for the sample mean using the formula \((sample mean - population mean) / (standard deviation / \sqrt{sample size})\).

Step 3 ：Find the critical z-score for a level of significance of 0.1, which is approximately 1.282 for a one-tailed test.

Step 4 ：Compare the calculated z-score to the critical z-score. If the calculated z-score is greater than the critical z-score, reject the null hypothesis.

Step 5 ：Calculate the z-score for the given data: \((7.1 - 6.8) / (0.7 / \sqrt{24})\), which is approximately 2.100.

Step 6 ：Since the calculated z-score (2.100) is greater than the critical z-score (1.282), reject the null hypothesis.

Step 7 ：Final Answer: The decision rule for rejecting the null hypothesis is if the z-score is greater than 1.282. In this case, the z-score is approximately 2.100, so we reject the null hypothesis. Therefore, the decision rule is \(\boxed{True}\).