Step 1 :We are given that the life expectancy of the relay microchip in a telecommunications satellite follows a normal distribution with a mean of 90 months and a standard deviation of 3.5 months.
Step 2 :We are asked to find the time for which the satellite should be insured such that there is a 94% confidence that it will last beyond the insurance date.
Step 3 :This is equivalent to finding the 94th percentile of the normal distribution with mean 90 and standard deviation 3.5.
Step 4 :We can use the inverse of the cumulative distribution function (CDF) of the normal distribution to find this.
Step 5 :Using the given mean of 90, standard deviation of 3.5, and confidence level of 0.94, we find the insurance time to be approximately 95.44170758108899 months.
Step 6 :Rounding this to the nearest month, we get \(\boxed{95}\) months.
Step 7 :Final Answer: The satellite should be insured for \(\boxed{95}\) months to be 94% confident that it will last beyond the insurance date.